Re: A fleur-de-lis Calendar

From: grapheus (grapheus_at_www.com)
Date: 06/05/04 

Date: 5 Jun 2004 08:39:39 -0700

Congratulations, Ole, for your NEW attempt in pushing the Calendaric
Solution !.. It's a lot better than the preceding ones, but there are
still some flaws in it !..

Hagen <dan5mark@yahoo.com> wrote in message news:<k7l1c0phiaujo8h37vlhc7nuug9h73gmlg@4ax.com>...
> Conditions:
> (1) A08 only contain 4 signs.

Possible !.. Nobody can say whether the 5th sign has been obliterated
voluntarily or by accident !..

> (2) The northern compartments contains an 18th thorn.

IMPOSSIBLE !.. There are NO TRACE of such a thorn !..

> (3) A31 is an intercalary week

An "ad-hoc hypothesis" to enhance the resemblance with the Mayan
Tzolkin "calendar", which is in fact a "Divination-Device". The TRUE
Mayan calendar is the "Tun" or the "Haab" !..

> (4) Signs and units are days, signgroups equal weeks. 7 or 8
> signgroups with alternately 29 or 31 signs are months.

The second hypothesis concerning the weeks is IMPLAUSIBLE !.. NO
known people has invented weeks with such a variable length !...

grapheus

>
> Move the 61th signgroup "A31" into the bull's eye, and unfold the two
> spirals to a single grand circle, that A30 is followed by B01 and B30
> by A01. Such circle has a periphery of 240 signs.

So, you are now back to your first solution : Arbitrarily ADDING A30
to B1/B7 and B30 to A1/A7!...

>
> Now displace the starting point from A01 one step back to B30, and
> count foreward 8 signgroups, accordingly B30, A01-A07, and continue
> with the next 7 signgroups.Make this shift eight times in total for
> the 61-1 signgroups. An enumeration will assure you that each 8 and 7
> signgroups contains 29 and 31 (months) visible signs by turn!
> This was all about the 243 signs which are visible on the Disc.
>
> If you are aware of my interpretation of this hieroglyphic
> inscription, you'll know that I plead that all signs form part of
> elements of always two signs. My method therby determines 70
> stem-elements together with 104 incomplete elements, because they only
> contain a single sign. In other words the inscription is in lack of
> 104 units. The same figure as the number of reduced elements.
>
> Imagine a compass card being placed in the middle of the grand-circle,
> appointing B30, A01-A07 as the western area, and A30, B01-B07 as the
> eastern area. The signgroups in those two corners contain together 31
> reduced stems or 31 absent units (if you can possess something
> absent.) The same pattern repeats itself for the 8 northern and 8
> southern signgroups, while it is somehow different with the 7
> signgroups sited northwest and the 7 in southwest with 29 units
> together, and finally for the northeast and southeast signgroups with
> 29 unit-days, thus forming a fleur-de-lis figure.
>
> This was my introduction to the missing season in the Phaistos Disc
> Calendar.
>
> Please try again the Fleur-de-lis calendar together with the above
> instructions:
> http://home.gvdnet.dk/~hagen/fleurdelis.htm
>
> Ole Hagen

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