Re: Pioneer Anomoly


"John C. Polasek" <jpolasek@xxxxxxxxxx> wrote in message
news:bkrgj1hono4co9hubd3kkn65ifoigo24s0@xxxxxxxxxx

> You're right, it must be unadjusted data. The first difference is 1.2
> Hz not 12, and I applied e-10 to the 10 digit number and the result is
> 1.256e-10/s^2 or 1/2 = 6.28e-9/s^2 very close by accident.
> But why should the received frequency be monotonically decreasing if
> something isn't accelerating?

Circular motion is always accelerating, it is just
the rotation of the planet. For Madrid, it is about
353m/s tangential velocity.

> 1.2 Hzz/min translates to nudot x lambda = 2.76e-2 m/ss or 31 million
> times Ap. or .0028 gee's.
> I need to see good data and of course being high is of no consequence,
> it's the rate of change.

As I say, it is a major task to analyse the data. It
is available but it is hundreds of megs and of little
use unless you are skilled at this sort of analysis.

George


.