Solar Eclipses seen by satellite (Forwarded)



European Organisation for the Exploitation of Meteorological Satellites
Darmstadt, Germany

Contact:
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March 23, 2006

Solar Eclipses seen by Satellite

On 29 March, the shadow of the moon will cross the Earth, resulting in a partial eclipse for most parts of Northern Europe.

For those of you interested in seeing more, Turkey or Northern Africa will be the place to go! In Germany the eclipse will -- hopefully -- be viewable between 11:40 in Southern Germany and 11:55 in Northern Germany with a black moon starting to cover the South Western rim of the sun.

An alternative is of course to follow the eclipse by satellite -- EUMETSAT has made a loop of the March 2006 eclipse here:

* Animation (AVI, 2314 KB <http://www.eumetsat.int/groups/ops/documents/multimedia/avi_eclipse_2006_29_03.avi>) of the eclipse, from 29 March 2006, 07:00 to 11:45 UTC. We see how the shadow of the Moon sweeps over the Atlantic Ocean, crosses the Sahara and over Turkey. The track of the Moon's shadow across Earth's surface is called the path of totality. It is typically around 16,000 kilometres long but only 160 kilometres or so wide. In order to see the Sun totally eclipsed by the Moon, you must be in the path of totality.

* Shadow of the moon crossing Turkey on 29 March at 10:45 UTC (JPG, 139 KB <http://www.eumetsat.int/groups/public/documents/image/img_jpg_homepage_eclipse01.jpg>).

* Global view of the eclipse, from MSG channel 2 (VIS0.8) (JPG, 540 KB <http://www.eumetsat.int/groups/ops/documents/image/img_jpg_eclipse_062903_ch2_big.jpg>). The eclipse is over Sahara, 29 March 2006, 09:45 UTC.

* The eclipse seen from MSGs High Resolution Visible channel (JPG, 426 KB <http://www.eumetsat.int/groups/ops/documents/image/img_jpg_hrv_eclipse_1268x861.jpg>). The eclipse is over Sahara, 29 March 2006, 09:45 UTC.

EUMETSAT's image gallery [<http://www.eumetsat.int/idcplg?IdcService=SS_GET_PAGE&nodeId=95&l=en>] contains several examples of the moon's shadow on the earth's surface captured during solar eclipses, including the total eclipse that occurred in August 1999 over Europe and of 4 December 2002 over the southern part of the Indian Ocean.

For more information on how satellite observations provide the scientific community with data on this phenomenon, the link below will take you to the webpages of Kees Floor, Dutch meteorological specialist and writer, who has provided a comprehensive overview on the eclipse phenomenon using EUMETSAT (and other!) satellite imagery:
http://www.keesfloor.nl/artikelen/zenit/zonsverd-sat/engels.htm
.



Relevant Pages

  • Re: Solar Eclipse Report 8/1/08
    ... eclipse consists of the sun-side of the earth being traversed by the ... moon's shadow, which is always there in space. ... shadow passes on at the edge of the earth and passes off elsewhere on ... the moon than noon is, and so the umbra may be non- ...
    (talk.origins)
  • Re: Early acronyms - Dutch businesses
    ... evening was the first time in my life, as far as I recall, that I've witnessed a total eclipse of the moon. ... The Earth's shadow at the Moon is considerably bigger than the Moon, so it takes a long time for the Moon to pass through the shadow. ... although I don't know why; I've never seen blood that colour. ...
    (alt.usage.english)
  • Re: US declares 1400-mile Pacific sat-shoot exclusion zone
    ... The eclipse is about 1% of this post, mostly about the satellite ... As will be evident, the barred area is a cool 1,400 miles long and ... Standard SM-3 interceptor, ...
    (sci.military.naval)
  • Re: Early acronyms - Dutch businesses
    ... I think you mean the spaces between the lines on the treble clef. ... The Earth's shadow at the Moon is considerably bigger than the Moon, ... This eclipse wasn't visible in Europe (because the ...
    (alt.usage.english)
  • ISS and the eclipse
    ... Whilst running a simulation of the sky as seen from Side, ... the time of the eclipse on the 29th, using Starry Night, I noticed ... that ISS was in the sky at the time of totality. ... satellite itself would, of course, only be illuminated by a 90 percent ...
    (uk.sci.astronomy)