Fixation rates for mutations by genetic drift

From: phillip smith (deletethis-phills_at_ihug.co.nz)
Date: 09/21/04 

Date: Tue, 21 Sep 2004 18:00:36 +0000 (UTC)

I wonder if any one can help me? I need to check a calculation for a paper.

>>From Kimura the time for a neutral mutation to be fixed is the mutation
rate.
If I have ten genes each of which can have a neutral mutation. What is the
mean time taken for there to be no individuals which are free of mutation.
That is the whole population carries at least one of the ten mutations

I think its is t =(1-u)^n

Where n is the number of genes that can have a mutation in this case 10 and
u is the mutation rate t = replications

I think I have made a mistake some where so any one who can put me right
would be appreciated

Cheers 

-- 
Phillip Smith
phills@(buggger).co.nz replace bugger with ihug
http://www.applied-evolution.co.nz
"he who is smeared with blubber has the kindest heart" -- a Greenland Eskimo
adage

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