Re: Applying TDF (was understanding y)


"John Edser" <edser@xxxxxxxxxx> wrote in message news:dioln2$unv$1@xxxxxxxxxxxxxxxxxxxxxx
> > Menegay's claim:
> >
> > Hamilton's rule applies in this model. That is:
> > 1. If rb>c, then both A and B will increase in frequency in this
> > population.
> > 2. If rb<c, then both A and B will decrease in frequency in this
> > population.
> > 3. If rb=c, then the frequencies of A and B will remain the same.
>
> JE:-
>
> Incorrect.
>
> 1. If (rb^e)>c, then both A and B will increase in frequency in this
> population.
>
> 2. If (rb^e)<c, then both A and B will decrease in frequency in this
> population.
>
> 3. If (rb^e) =c, then the frequencies of A and B will remain the same.
>
> Where e = minimally the number of chromosomes within just a minimally
> correct heuristic model which in this case is two.

I am happy to have your claims for what the model will show to
place beside my claims. However ...
What you wrote here is different from what you have written before.
I suspect a typo. Do you mean:

r (b^e) > c
or
(rb)^e > c
or
(r^e) b > c

I would have thought that you meant the third, since the probability
that both epistatic genes are IBD is (r^e).

Since you didn't comment upon my modeling assumptions, I assume you
have no objections. Once you clarify what you are claiming regarding
'e', I will proceed with my analysis of the model and we can determine
whether your claims regarding 'e' are justified, or whether Hamilton's
rule (aka Menegay's claims) is a better conclusion given our agreed
modeling assumptions.


.