Re: In energy, what does work equal?

From: Herman Family (celcaps_at_frontiernets.net/without_any_s/)
Date: 08/06/04


Date: Fri, 06 Aug 2004 02:43:36 GMT


"Hikaru" <none@available.com> wrote in message
news:4112d5b0$0$5262$c3e8da3@news.astraweb.com...
> > > What about the relationship between enthalpy and internal energy?
> >
> > This came up in a previous thread from you no? The bottom line is
(again)
> > this: at constant volume, dE = q; at constant pressure dH = q. This is
> the
> > primary reason why H is defined, as most experiments are carried out at
> > constant pressure.
>
> Hm ok I'm not quite understanding this right now. dE and dH both give you
q.
>
> I guess the original equation is dH = dE + d(PV)
>
> I'll think like the piston thing. At constant pressure, expansion would
> lower temperature so heat would be draw in, so q is positive. At constant
> volume, more heat would mean more pressure...q is positive here, too. I'm
> lost, sorry.
>
>
I think my books use U where you are using E.
In the piston, at constant pressure, lowering the temperature (removing
heat) would decrease the volume, and q is negative.
Now, the heat that you took out of the system should equal the work done on
the system, or PdV. Notice that since V decreased, work was done on the
system, so it recovered a bit of energy from that, allowing it to keep the
pressure up.

Lets then go a little further and add heat to the system. The internal
energy thus starts to rise, but this allows for the piston to expand. q is
now positive and work leaves the system. E is a state variable, dependent
upon temperature and pressure.

H is E without the piston work, sort of. It is the total q to achieve a
given temperature and pressure less the work required to increase the
pressure. To get E from H, just subtract any piston work required.

I've probably screwed a couple things up, but if heat is lost from a system
q is negative. If the system stays at the same temperature and pressure
then q = PdV.

Michael



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