Re: % HCl

From: Marshall Dudley (mdudley_at_king-cart.com)
Date: 01/20/05 

Date: Thu, 20 Jan 2005 16:47:14 -0500

farooq_w@hotmail.com wrote:

> Sol, of AgCl = (2 x 10^-10)/[Cl] + b + 3.4 x 10^-5 x[Cl]

> Oh, I forgot the most important thing, the units. Square brackets
> should have given a hint. Every term has molarity units, of course
> including the solubility. How hard working and sincere people were of
> those days!

Hmm. I guess the [Cl] also contains the Cl ions in the AgCl that is being
dissolved. If it didn't then the equation would explode with /[Cl] in the
denominator of the first term giving infinate solubility in distilled
water. Odd they didn't factor that part out.

Thanks,

Marshall