methlymalonic acid reaction with Na OH

hi,

i have tried this problem for a while but i cannot get it

i think the formula for methylmalonic acid is this:
(CH3)2C(CO2H)2

if i react with it sodium hydroxide (NaOH) what will the products be?

please help :| i know H2O is in there, and i swear i have tried. i know it
loses a H from this: (CH3)2 C (COOH)2

and i think the ans is this:

(CH3)2 C (COOH) (COO-)Na+

but it's diprotic so how come it only looses 1 H?


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