Re: methlymalonic acid reaction with Na OH

On Tue, 29 Nov 2005 20:14:33 +0000 (UTC), "Panther" <black@xxxxxxx>
wrote:

> hi,
>
>i have tried this problem for a while but i cannot get it
>
>i think the formula for methylmalonic acid is this:
>(CH3)2C(CO2H)2
>
>if i react with it sodium hydroxide (NaOH) what will the products be?
>
>please help :| i know H2O is in there, and i swear i have tried. i know it
>loses a H from this: (CH3)2 C (COOH)2
>
> and i think the ans is this:
>
>(CH3)2 C (COOH) (COO-)Na+
>
>but it's diprotic so how come it only looses 1 H?

So remove the second one.

(It would depend on how much NaOH you add.)

bob

.

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