question on solution thermodynamics

If I have a vessel filled with a liquid: 0.019 mole fraction ethanol
and 0.981 mole fraction water (1.9 mole % ethanol, 98.1 mole % water),
thermodynamic tables tell me that at 95.5 degrees C, the vapor will be
17 mole % ethanol, 83 mole % water.

But what about if the temperature is not 95.5 degrees C?

Between room temperature (20 C, for instance) and 95.5 C, will the
vapor in equilibrium with the previously mentioned liquid still have 17
mole % ethanol?

.

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