Re: How do I calculate evaporative losses?
- From: "John M." <john_howard_morgan@xxxxxxxxxxxxx>
- Date: 22 Nov 2006 12:08:08 -0800
BAJJERFAN wrote:
lcc wrote:
On Tue, 21 Nov 2006 22:25:21 +0100, <elephantiasis@xxxxxxxxxxxxx> wrote:
I'm looking at a reaction involving methanol for making biodiesel from
vegetable oil. Methanol and caustic soda are mixed and added to
vegetable oil. The reaction takes place at a range of temperatures
between 40 and 65 degrees and usually lasts for an hour. The products
are biodiesel and glycerine.
It can take place in a sealed vessel but more usually is done in a
vessel with a lid which is not sealed.
I'm expecting some of the methanol will be lost by evaporation to
atmosphere but how can I calculate the likely losses?
It's complex matter. Depend on temperature (Methanol boil at 64C), vessel
and lid.
Methanol is a poison, it has to be done in ventilated area. Why can't yuo
use condenser ?
Lucas
--
Using Opera's revolutionary e-mail client: http://www.opera.com/mail/
Anyone care to speculate on the source of the glycerine since this
would be a product of saponification of beef fat but hardly would be
expected to arise from hydrolysis of veggie oil. Glycerine is usually
found in fats of animal origin. You makin moo-diesel?
All common fats and oils are glycerides. Read:
http://en.wikipedia.org/wiki/Vegetable_oil if you don't believe me
.
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