Re: chemical equilibrium
- From: "Ron Jones" <ron@xxxxxxxxxxxxxxx>
- Date: Wed, 19 Mar 2008 19:43:17 -0000
b201b402cd21c3@xxxxxxxxx wrote:
Consider the reaction:
A -> B + C
If the reactor already has substantial B and C in it, the reaction
will not proceed as far to the right as it would without B and C (Le
Chatelier).
What if the reactor has substantial C, but no B in it? Will the
reaction still proceed as though it had been devoid if both B and C?
It's too dependant on the rate constants to generalize.
A -> B + C can also be the equation for a firework / runaway reaction - the
presence of extra C will slow the reaction (by absorbing heat and reducing
the temperature rise), but it's still going to go to completion.
--
Ron Jones
Process Safety & Development Specialist
Don't repeat history, unreported chemical lab/plant near misses at
http://www.crhf.org.uk Only two things are certain: The universe and
human stupidity; and I'm not certain about the universe. ~ Albert
Einstein
.
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