Re: 0.20 delay in 6v control circuit

From: Bob (bfraser1www_at_optonline.net)
Date: 11/10/04


Date: Wed, 10 Nov 2004 03:11:55 GMT

On Wed, 10 Nov 2004 00:06:46 GMT, Robert Monsen
<rcsurname@comcast.net> wrote:

>Bob wrote:
>> On Mon, 08 Nov 2004 22:10:19 GMT, Robert Monsen
>> <rcsurname@comcast.net> wrote:
>>
>>
>>>(fixed top posting below. Please post replys after the main body of
>>>text. It's just convention here)
>>>
>>>Bob wrote:
>>>
>>>>On Mon, 08 Nov 2004 07:37:01 GMT, Robert Monsen
>>>><rcsurname@comcast.net> wrote:
>>>>
>>>>
>>>>
>>>>>Here is a slightly better circuit for you needs:
>>>>>
>>>>> 6V
>>>>> ----------------------------o--o
>>>>> | | |
>>>>> | - C|
>>>>> | o ^ C| Relay Coil
>>>>>|=| switch | C|
>>>>> | o | |
>>>>> | '--o
>>>>> | |
>>>>> | 10k |/
>>>>> o---/\/\/--o-----o-----------|
>>>>> | | | |>
>>>>> | | | |
>>>>> o----|<----| | + |
>>>>> | * --- 220uF |
>>>>> / --- |
>>>>> \ | |
>>>>> / 1k | |
>>>>> \ | |
>>>>> | | |
>>>>> | | |
>>>>> '----------------o-------------'
>>>>> GND
>>>>>
>>>>> * Schottky Diode
>>>>>
>>>>>created by Andy´s ASCII-Circuit v1.25.250804 www.tech-chat.de
>>>>>
>>>>>The base will drop immediately from 850mV to about 200mV when the switch
>>>>>is opened, due to the 1k resistor and the schottky diode. When the
>>>>>switch is closed again, the base will come up from 200mV to about 850mV
>>>>>before the transistor conducts, so
>>>>>
>>>>>V(t) = V ( 1 - exp(-t/RC) )
>>>>>
>>>>>thus
>>>>>
>>>>>t = -ln(1 - .65/6) * 10k * 220u
>>>>> = .25s += 0.05s
>>>>>
>>>>>Once the cap is charged up, the current will be about 500uA, so the
>>>>>current through the transistor can go up to 25mA (assuming a beta of 50).
>>>>
>>>>
>>>>Thanks again Robert,
>>>>
>>>>Do you have any idea on the specs for the diodes needed. I went to
>>>>pick up the Schottky diode and the one in parallel with the relay but
>>>>was not able to choose from the variety available. Thanks for the
>>>>design.
>>>>
>>>>Bob
>>>>
>>>>
>>>
>>>You can use any of 1N4002-1N4007 diodes for both of them. A Schottky
>>>diode would be nice where the * is (it doesn't have to carry any
>>>appreciable current, so any of them will do) but isn't necessary. It
>>>just makes the recovery time a bit better, because it has a lower
>>>forward voltage drop.
>>
>>
>> As you can probably tell, this is the first time I ever posted to a
>> news group. Anyway I built the circuit as you designed. What
>> actually occurs is the relay is energized for only .20 seconds instead
>> of a delay of .20 seconds then energized until the switch opens. (Did
>> you expect this? I checked the path of the circuit 3 times)
>>
>> Bob
>
>When you close the switch, it should take 0.2 seconds to charge up the
>capacitor enough to turn on the transistor. Thus, assuming the relay is
>open when you start, the following should happen:
>
>1) relay open, switch open
>2) switch closed
>0.2 seconds
>3) relay closed
>...
>4) switch open, relay opens immediately.
>
>It sounds like you have the 10k resistor and 220uF capacitor swapped.
>That would cause it to
>
>1) relay open, switch open
>2) switch closed, relay immediately on
>0.2 seconds (or less!)
>3) relay open
>...
>4) switch open, relay still open
>
> From your reply, I can't quite figure out whether that is what you are
>seeing, though.
>
>(You probably know this, but closed means passing current, open means
>unable to pass current.)

Thanks so much for all the assistance. I am amazed with your patience
with an electonic baby. It appears the Transistor is the culprit.
Maybe undersized? I replace a Radio Shack #276-1617 (tiny) with a
Radio Shack #276-2020 also known as a TIP3055. The ciruit works like
a charm. Using a digital video camera, (consumer grade (Sony)), I am
able to count a .22 second delay now compared without this delay
circuit. Thanks again and my hat comes off for your patience and
expertise with this circuit design.

Bob Fraser



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