Re: Need help with a circuit
From: Active8 (reply2group_at_ndbbm.net)
Date: 12/28/04
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Date: Tue, 28 Dec 2004 18:43:32 -0500
On 28 Dec 2004 14:31:25 -0800, Dark Alchemist wrote:
> Hmmm, I was able to get all the way to the last part on my own but even
> looking at what you did (where I see an and gate) I am lost.
>
> So, I have two ouputs (A, B) and your logic table works. Now all I
> need to do is take the A AND B = 0 or 1 in this instance. I noticed
> that 0<x<1 1 1 . 1 and 1 is 1 while 0 and 1 or 1 and 0 = 0
> so would it not be simpler to (A AND B) * sqrt(1-x^2)? The product of
> that would be 0 or the sqrt part.
That's very good! But you'd need an analog multiplier that works at
DC if you go there. John simply used A && B as an enable, a much
better approach.
-- Best Regards, Mike
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