Re: Need help with a circuit

From: Active8 (reply2group_at_ndbbm.net)
Date: 12/29/04 

Date: Tue, 28 Dec 2004 20:48:38 -0500

On 28 Dec 2004 16:18:01 -0800, Dark Alchemist wrote:

> Hmmm, I am not grasping beyond the and part from what he was telling
> me. :(
> We have A && B then what? From this point on is where I got lost.

They turn the sqrt circuit on or off. Off would be x < 0 OR x > 1.
So when the sqrt is off, it should output zero.

My point was that if you try to do (A && B) * sqrt, the * implies
analog multiplication wheras && or AND is digital multiplication.

Now you can analog multiply sqrt with 1 or 0, the circuitry won't be
as simple, however. So use A && B as a control, i.e., an enable.

I still think that you coming up with (A AND B) * sqrt(1-x^2) was
very good. It's true. 

-- 
Best Regards,
Mike