Re: Need help with a circuit
From: John Fields (jfields_at_austininstruments.com)
Date: 12/29/04
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Date: Tue, 28 Dec 2004 20:59:37 -0600
On 28 Dec 2004 17:13:11 -0800, "Dark Alchemist"
<GhostOfACPast@gmail.com> wrote:
>So, was my simplification still holding the same as the original?
>Btw, thank you everyone for you help. :)
---
Dunno, for sure...
Modifying the circuit a little and looking at the circuit and the
truth table, we have:
+2V
| Vcc
[10.0K] |
| [10K]
+----|+\ |
| | >--+----+
x>---+--[10K]--------|-/ |
| | Vcc | +-------+
| [10.0K] | | 0V---|b |
| | [10K] +--B | _ |
+--[10k]--------|+\ | and AB------|a/b y|---y
| | | >--+-------A | |
| +----|-/ +----|a |
| | | +-------+
| GND | S1
| |
| |
| +-------+ +-------+
| 1V--|1 | +----------------+ |
| +------+ | 1-x²|--|1-x² sqrt(1-x²)|--+
+--|x x²|--|x² | +----------------+
+------+ +-------+
The blocks on the bottom are your circuits, and sqrt(1-x²) is shown as
being routed through a switch where the output (y)is either sqrt(1-x²)
or 0, depending on whether is x is <=0V, between 0V and 1V, or >1V.
The AND gate only goes true when 0V<x<1V, with the result that the
switch will be turned off when x is outside the limits, and at those
times y will be equal to 0V, like this:
x A B y
--------+-----+-----+-------------
<=0V 0 1 0
0V<x<1V 1 1 sqrt(1-x²)
>=1V 1 0 0
--
John Fields
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