Re: Need help with a circuit

From: John Fields (jfields_at_austininstruments.com)
Date: 12/29/04


Date: Tue, 28 Dec 2004 20:59:37 -0600

On 28 Dec 2004 17:13:11 -0800, "Dark Alchemist"
<GhostOfACPast@gmail.com> wrote:

>So, was my simplification still holding the same as the original?
>Btw, thank you everyone for you help. :)

---
Dunno, for sure...
Modifying the circuit a little and looking at the circuit and the
truth table, we have:
               +2V                              
                |         Vcc                    
             [10.0K]       |                      
                |        [10K]                 
                +----|+\   |            
                |    |  >--+----+
x>---+--[10K]--------|-/        |
     |          |         Vcc   |             +-------+ 
     |       [10.0K]       |    |        0V---|b      |
     |          |        [10K]  +--B          |  _    |
     +--[10k]--------|+\   |      and AB------|a/b   y|---y
     |          |    |  >--+-------A          |       |
     |          +----|-/                 +----|a      |
     |          |                        |    +-------+
     |         GND                       |       S1
     |                                   |
     |                                   |                      
     |            +-------+              +-------+
     |        1V--|1      |  +----------------+  | 
     |  +------+  |   1-x²|--|1-x²  sqrt(1-x²)|--+
     +--|x   x²|--|x²     |  +----------------+  
        +------+  +-------+
                                      
The blocks on the bottom are your circuits, and sqrt(1-x²) is shown as
being routed through a switch where the output (y)is either sqrt(1-x²)
or 0, depending on whether is x is <=0V, between 0V and 1V, or >1V.
The AND gate only goes true when 0V<x<1V, with the result that the
switch will be turned off when x is outside the limits, and at those
times y will be equal to 0V, like this:
   x       A     B         y
--------+-----+-----+-------------
  <=0V     0     1         0
         
 0V<x<1V   1     1     sqrt(1-x²)     
  >=1V     1     0         0 
 
-- 
John Fields


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