Re: RLC
- From: "Lord Garth" <LGarth@xxxxxxxxxxxx>
- Date: Sat, 09 Apr 2005 03:01:57 GMT
"jason" <cheanglong@xxxxxxxxx> wrote in message
news:1113012199.217502.93840@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
> Hi Garth
>
> Thank you
> My understand is most current will be in the tank circuit no matter it
> is series or parallel LC tank.
I think this is a point of view, whether you are looking at what happens
inside the LC or what happens when you mentally replace that LC with
a black box of impedance Z and consider the whole circuit.
We have been discussing what happens inside the LC and then applying
that to the what happens to the remainder of the circuit. Our point of
view has been shifting and this can be confusing.
In a series resonant LC, maximum current flows through LC and the rest of
the oscillator circuit.
In a parallel resonant LC, maximum current is contained within the LC tank.
Which implies that minimum current flows through the rest of the oscillator
circuit.
You've got to mentally step back and replace the resonant LC with its
resultant Z then look at the voltage across that Z
> That means I am wrong?
No, its just a matter of whether your looking at the whole oscillator or
just the
LC portion alone.
In either case, the losses are made up for by the active component or the
system losses would dampen the oscillition and the circuit would ring to
a stop. A mechanical equivalent would be a cymbal on a drum set, hit it
once and it oscillates with a decreasing amplitude until it stops. Add an
active component (a drummer that adds more energy to the system) and
oscillation will continue until the input ceases, then the decay proceeds.
>
> Thanks a lot
>
> jason
>
.
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