Re: coutdown 555 timer values?
- From: Bob Monsen <rcsurname@xxxxxxxxxxx>
- Date: Tue, 26 Jul 2005 21:59:57 -0700
John Fields wrote:
Then, of course, there's always:
VCC>------+----+
| | V+ | [RT] | | | [10K] [R7] +----|-\ | | | | >--+-->180s
+----|----|+/ | | V+ | | | [R6] | [10K] | +----|-\ | | | | >--+-->150s
+----|----|+/ | | V+ | | | [R5] | [10K] | +----|-\ | | | | >--+-->120s
+----|----|+/ | | V+ | | | [R4] | [10K] | +----|-\ | | | | >--+-->90s
+----|----|+/ | | V+ | | | [R3] | [10K] | +----|-\ | | | | >--+-->60s
+----|----|+/ | | V+ | | | [R2] | [10K] | +----|-\ | | | | >--+-->30s
+----|----|+/ | |
| +----D
[R1] | G--+
| [CT] S |
| | | |
GND>------+----+----+ |
_ |
R/T>---------------------+
In this circuit we use six comparators with references derived ratiometrically from Vcc, which will make the circuit insensitive to longish-term variations in Vcc. The circuit works by applying a short positive pulse to the gate of the MOSFET, which discharges CT and forces all of the inverting (-) inputs to the comparators lower than the reference voltages on their non-inverting (+) inputs. This will cause all of the outputs to go high. Then, when CT charges it will rise through each of the reference voltages on the + inputs sequentially, turning each of the comparators ON sequentially, forcing, and holding, their outputs low, one at a time.
In order to determine the widths of the various outputs we can use
Vcc T = RC ln ----------- = kRC Vcc - Vth
to determine what the voltages will be on the - inputs of the comparators at the times we're interested in.
I know the thread took a left turn, but I'll just point out that one may want to use a constant current source to charge CT. Then, all the resistors can be identical. If I is constant, dV/dt is also constant. One can get quad packages of comparators...
-- Regards, Bob Monsen
If a little knowledge is dangerous, where is the man who has
so much as to be out of danger?
Thomas Henry Huxley, 1877
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