Re: Right resistor for high power LED for sound reader?

On Thu, 11 Aug 2005 01:10:04 +0000, Don Klipstein wrote:

> In article <qi4lf1pa68potjgkt3ep6oj58jlbshqp59@xxxxxxx>, John Fields wrote:
....
>> P = I²R = 0.316A² * 5R = 0.5W
>>
>>So, since the 10 ohm resistor is dissipating one watt and the set of
>>paralleled resistors is dissipating half a watt, the array is
>>dissipating 1.5 watts.
>
> Thanks... I did screw that one up.

But Ten Ohms will fry his LED! Take SIX pcs. 10 ohm, two watt, and
put them 3x2 for 15 ohms at SIX watts! :-)

Cheers!
Rich

.

Relevant Pages