Re: total resistance in parallel circuits



Midnight Oil wrote:

> I am new to electronics, and I've been learning the basics of ohm's
> law. I ran into the formula for finding the total resistance in a parallel
> circuit, struggled with it's meaning...and I want to be sure I understand
> the formula:
>
>
> R(tot) = 1
> -------------
> 1 + 1 + 1
> -- -- --
> R1 R2 R3
>
>
> I broke the formula down like this:
>
>
> R(tot) = 1 <--- E (volts)
> ---------------
> 1 + 1 + 1
> -- -- -- <--- I (amps)
> R1 R2 R3
>
>

That's not a bad way to interpret what's going on. But, to make the
units work out properly, we could multiply the expression by 1V/1V
(since that equals 1 and multiplying by 1 is allowed), then manipulate
things like this:

1 1V
R(tot) = ---------------- x ----
1 1 1 1V
-- + -- + --
R1 R2 R3


1V <--- E (volts)
= ----------------
1V 1V 1V
-- + -- + -- <--- I (amps)
R1 R2 R3


So each resistor has 1V across it, and has (1V/Rx) current flowing
through it.

Regards,

Mark

p.s.

>
> The Moon is Waxing Crescent (7% of Full)

Hmmmm. Years ago I had DOS version of that program. Is there
something available for Windows these days?

.



Relevant Pages

  • Re: total resistance in parallel circuits
    ... > I am new to electronics, and I've been learning the basics of ohm's ... > law. ... I ran into the formula for finding the total resistance in a parallel ... I saw this derived from the sum of conductances: ...
    (sci.electronics.basics)
  • Re: Why is -1 * -1 = 1 ?
    ... Why does multiplying two negative numbers create a postive number? ... it just a law of arithmetic? ... I am struggling to find an intuitive ... explanation. ...
    (sci.math)
  • Why is -1 * -1 = 1 ?
    ... Why does multiplying two negative numbers create a postive number? ... it just a law of arithmetic? ... I am struggling to find an intuitive ... explanation. ...
    (sci.math)
  • Re: 683 lm/W, how was this calculated?
    ... platinum emitting about .892 watt in the 400-700 nm range. ... Using Planck's law and multiplying by VI get ... W/cm^2 for a black body at 2042 K. ...
    (sci.engr.lighting)

Quantcast