Re: Transmission Gate question


<jwelser@xxxxxxxxxxxxxxxxxx> wrote in message
news:dro3gg$sa3$2@xxxxxxxxxxxxxxxxxxxxxxxx
> Noway2 <no_spam_me2@xxxxxxxxxxx> wrote:
>
> : Most text books focus too much on the Id = k(Vgs - vt)^2 equation.
> : Unless you are getting into semiconductor physics, this equation is
> : probably about worthless. It may help for you to look at some
product
> : data sheets for fets and look at the curves relating on resistance
> : versus the Vds and Vgs.
>
> It's more a distinction between analog and digital circuits,
> rather than semiconductor vs (? -- MOSFETs are semiconductors.)
Devices
> in CMOS digital circuits spend most of their time in either the cutoff
or
> the linear region, only passing through the saturation region (whose
drain
> current is roughly given by the equation you presented above) when
they
> are switching. On the other hand, most useful analog circuits involve
> amplifiers, which rely on devices that exhibit the controlled
> current-source behavior characteristic of the saturation region of
> operation.

I think you mean "linear" where you say "saturation" and vice versa.

.