Re: 48 DCV battery design

On 29 Sep 2006 02:02:23 -0700, in message
<1159520543.255216.254310@xxxxxxxxxxxxxxxxxxxxxxxxxxx>, "mark2006"
<iKolar26@xxxxxxxxx> scribed:

I have connected 19 "small" homemade batteries into one realy,
realy huge battery. After some tests and after fixing some problems
with volmeter, i have this situation:

One "small" battery:
DCV : 2,53 V
DCAmps: : 0,5 mA

Huge battery:
DCV : 48V
DCAmps : 24 mA

I believe your math is a bit off. It would take 912 (not 19) 2.53V .5mA
cells to make a 48V 24mA battery. To wit:

48V * 24mA = 1152VA

2.53V * 0.5mA * 19 = 24.035VA

1152VA / 24VA = 48

So you need 48 columns of 19 rows of 2.5V .5mA cells. Only 47 more to go.
Keep us posted.

.

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