Re: capacitances in parallel


Phil Allison wrote:
<fathahrahman@xxxxxxxxx> wrote in message
news:1167799155.705235.18330@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx


** Groper alert !


It is seen that the capacitances in parallel add up.
the equations are

Q= Q1/V +Q2/ V

= (Q1+Q2)/V

Being Q=CV

Ceq=(C1+C2)

But how do the charges in parallel add up.What is its physical meaning
or implication.


** Your Q lacks context and hence is not defined.

Are you asking about connecting two CHARGED capacitors in parallel ?

If so, the Qt ( total charge ) afterwards is the sum of the two Q values.

Also, Qt = ( C1 +C2) x V

where V is a new voltage of the combined capacitor.





....... Phil

The 'Q' mentioned was the charge inside the capacitor
There is a small coorection to the first equation I provided.

Ceq=Q/V=Q1/V+Q2/V

where Q1 and Q2 arethe charges inside capacitors C1 and C2 and V is the
voltage.

I am not concerned about the equation side. I am concerned about how
the capacitances in parallel in add up.For comparison I shall say, the
value of two resistances in series is the sum of te two resistance
since the voltage supplied to the resistors will distribute itself
between both of them.

Equationwise,
V=V1+ V2= iR1 + iR2=i(R1+R2)

But how does it materialize in Cap. in II. Plz. give the reason ..
Charge distribution or voltage distribution or anything else?
How does it affect the value of the capacitance.

Regards,
Robotnik

.

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