Re: Human Electrocution: How is the resistance not ridiculously high?
- From: John Popelish <jpopelish@xxxxxxxx>
- Date: Thu, 03 Apr 2008 12:25:26 -0500
Tomás Ó hÉilidhe wrote:
I've been doing electronics for three years now but I don't understand
how a person can be electrocuted by touching one part of the circuit
in a mains supply.
If I hold one lead of an ohmmeter in my left hand, and the other in my
right hand, it registers the resistance to be approximately 2
megaohms, which is ridiculously high.
Now if I hold one lead in my hand, and dig the other into the grass,
it doesn't even register -- I may as well be holding the leads apart
in thin air.
Current = Voltage divided by Resistance
Current = 230 volts divided by 2 megaohms = 115 microamperes
115 microamperes is nowhere near enough to electrocute someone.
So lets say I stick a metal rod into the socket on the wall. The
current has to flow thru my hand, down to my foot, thru my cotton
sock, thru my shoe, thru the wooden floorboards, thru the concrete,
thru the clay down to the metal rod we call ground. Now excuse me, but
is that not a RIDICULOUS amount of resistance, up in the gigohms
somewhere?
It may sound like I'm denying that people get electrocuted -- I'm not,
I realise that people do get electrocuted. But I can't for the life of
me understand how enough current can flow, given the massive
resistances that are involved.
Can anyone enlighten me?
Do the calculation again but with the other hand on the water tap or the grounded case of an appliance.
--
Regards,
John Popelish
.
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