Re: Effect of the supply internal resistance


"Rich" <notty@xxxxxxxxxx> wrote in message
news:6v6cq1Figba3U1@xxxxxxxxxxxxxxxxxxxxx

In the circuit above the center point, which is kind of a reference point
is
within R1. It's 40.5 Ohms into R1 on one side. Other side is 40.5 Ohms.
Adding resistances from the center point either way adds up to 50.5 Ohms,
so
total is 101 Ohms. True center point, which I suppose is a reference
point
is total resistance divided by 2.

40.5 Ohms and 49.5 Ohms.


NO! NO! NO!

You have the battery and R(internal), This is your source. Then you have
your voltage divider and you want the voltage across the 10 ohm resistor.
See Neds description of how to work out the circuit, it is the proper method
that is taught in schools and books. You don't use an imaginary reference
point, you're over complicating the circuit, the only reference point to use
is battery neg (common).

Shaun


.

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