Re: Need resistor help please (35w x 12v)
- From: Franc Zabkar <fzabkar@xxxxxxxxxxxxxxxxx>
- Date: Sun, 19 Feb 2006 13:52:18 +1100
On 13 Feb 2006 14:27:49 -0800, "Locu" <loculogic@xxxxxxxxx> put finger
to keyboard and composed:
Ahh, good point on the light striking surface and turning into heat.. I
hadn't thought of that.. pretty futile maneauver except perhaps to
spread the heat a little i guess.
Well, I installed HID (xenon) lights in my non-xenon equipped vehicle.
The projectors are designed for xenon's though, just it didn't come w/
that option. I bought an OEM kit, and everything is there, except the
stock wiring doesn't support the high amp load the startup of the HID's
draw which can be upwards of 100watts I understand. So I used the
existing wiring to a relay, to turn on/off my wiring harness which
brings power direct from the battery thru fuses to the HID lights.
Now since I bypassed the cars internal wiring, the car see's no light
bulbs in there, so it complains.
I'd suggest modifying the device that monitors the lamps, assuming it
is accessible from a maintenance point of view.
Let's assume this device works by monitoring the voltage drop in a
series resistance by means of a comparator, as follows:
BAT+ O--+- Rsense --+-O O---- 55W lamp ----O BAT-
| |
|___ ___|
| |
__|____|__
\ /
\ Comp /
\ /
\ /
\/
In this case you could remove the sense resistor and transfer it to
the new, heavier gauge, relay switched lamp circuit, as follows:
+= Rsense ==+
BAT+ O==+= Rsense ==+=O O==== 100W lamp ====O BAT-
| |
| |
O O
O O
| |
|___ ___|
| |
__|____|__
\ /
\ Comp /
\ /
\ /
\/
To maintain the same voltage drop for a 100W lamp as for the original
55W one, just use the equivalent of two identical sense resistors in
parallel. Doing it this way might only require a cheap 5W Al-clad
resistor.
- Franc Zabkar
--
Please remove one 'i' from my address when replying by email.
.
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