Re: Timer circuit help

From: Terry Pinnell (terrypinDELETE_at_THESEdial.pipex.com)
Date: 11/23/04 

Date: Tue, 23 Nov 2004 17:38:24 +0000

Fred Bloggs <nospam@nospam.com> wrote:

>You don't need any NOR gates whatsoever- you take Qn+3 and stuff a one
>on that RTC input of the oscillator , pin 10, through a diode and the
>4060 freezes in Qn=0 state which is the turn-on polarity for the bulb.
>The n runs 1-14 and then RT x CT= 1/(2.3*6Hz*2^n) by the data ***.

Thanks - I'll try that when the 4060s I've ordered arrive. (If time
allows, I also plan to try your 555 solution, and John Fields' shift
register approach.) Meanwhile, as mentioned, I'd like to simulate with
4020. Just about to study JF's post on that. 

-- 
Terry Pinnell
Hobbyist, West Sussex, UK