Re: Is zero even or odd?
From: Fred Bloggs (nospam_at_nospam.com)
Date: 12/21/04
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Date: Tue, 21 Dec 2004 10:37:35 GMT
Kevin Aylward wrote:
> Fred Bloggs wrote:
>
>>Alfred Z. Newmane wrote:
>>
>>>Nicholas O. Lindan wrote:
>>>
>>>
>>>>"John Sefton" <john@petcom.com> wrote
>>>>
>>>>
>>>>
>>>>>0 can't be divided by itself,
>>>>
>>>>Sure it can: 0 / 0 = 0 * (1 / 0) = 0 * infinity = 1
>>>>
>>>>It works if the only three numbers in the universe are
>>>>0, 1, and infinity -- A number system that seems very
>>>>suited to usenet.
>>>
>>>
>>>Except for the fact that: 0 / 0 = undefined
>>>
>>>Or actually more correct: n / 0 = undefined
>>>
>>>
>>
>>0/0={ SET OF ALL INTEGERS }
>
>
> No.
>
>
>>n/0= NULL SET for n<>0
>>
>>It is very well-defined.
>
>
> No it isnt.
>
> Kevin Aylward
You apparently have stumbled on something else you know damn little
about. In case you need help with this , you might note that "/" is NOT
an operator on the integers, it is the "inverse" of a multiplication
operator. Inverse is a well-defined concept but not necessarily a
function, it is a set theoretic mapping. E.G. m/n={ q: m=q*n} by
definition, so that m/n which is actually a set which can be empty, a
singleton, or infinite. In the case of m/n, it is then m/n = F^-1(m)
where F(x)= n*x. Your reasoning would lead one to believe /: I x I -> I
is a function, which it isn't.
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