Re: Common emitter amplifier question (rc || rl)

From: lemonjuice (exskimos_at_anonymous.to)
Date: 02/02/05 

Date: 2 Feb 2005 00:46:03 -0800

On Tue, 1 Feb 2005 16:50:34 -0500, Active8 <reply2group@ndbbm.net>
wrote:

>On 1 Feb 2005 12:48:52 -0800, lemonjuice wrote:
>
>> On Sun, 30 Jan 2005 09:06:35 +0000, John Woodgate
>> <jmw@jmwa.demon.contraspam.yuk> attempted to answer
>>
>>>I read in sci.electronics.design that cheese9988
>>><cheese9988@hotmail.com> wrote (in
>> <1107034758.554400.279030@c13g2000cwb
>>>.googlegroups.com>) about 'Common emitter amplifier question (rc ||
>>>rl)', on Sat, 29 Jan 2005:
>>>>Hi, I have been trying to figure this out and its bugging me. On a
>>>>common emmitter amplifier, you have rl (load resistance) and rc
>>>>(collector resistor). How are these two in parallel with an ac
>> signal?
>>>>It looks more to me like rl is in parellel with the transistor and
>> both
>>>>being in series with rc. Can anyone explain this?
>>>>
>>
>>>As far as the signal is concerned, the collector DC supply is at
>> ground
>>>potential (or should be).
>>>
>> stop wasting bandwidth by repeating his question. The question is
>> why is it at Ground. Either give an answer or go and mow your lawn.
>> Maybe you're Kevin Alyward under a different name?
>
>Maybe he is, but no matter what you call yourself, you're an
>***.

Oh sure I'd love to be called that. Yes I sure remember when I
untangled you saying that the gain between 2 amplifier stages was
equal to the sum of the gains of each individual stage! Do you need
the url on that?
Now Mr. Brainy can you answer the guys elementary question above?