Re: Q factor
From: Tim Wescott (tim_at_wescottnospamdesign.com)
Date: 03/21/05
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Date: Sun, 20 Mar 2005 19:25:18 -0800
jason wrote:
> Hello All
>
> Say Impedance Z i = jwL + Rs
> (Rs is in series and it is actually the internal series resistance,
> this means inductor is an ideal one)
>
> So if we assume this way, then does it mean jwL comes from the ideal
> inductor? Not from any of the Rs at all?
>
> If we want to find Q of the inductor
> we will use Q= wL/Rs where SL(or jwL) is not involved totally in the Q
> equation.
>
> Am I right ?
> Kindly enlighthen
> Thank you
>
>
> Jason
>
If your actual inductor acts exactly like a perfect inductor in series
with a resistor yes. Otherwise no. Many times in RF work your actual
inductor will either act like it has both series and parallel loss, or
(probably closer to reality) like it's transformer-coupled to a lossy
circuit. This is why if you plot the Q of an inductor against frequency
it'll come to some broad peak then slip down again.
-- Tim Wescott Wescott Design Services http://www.wescottdesign.com
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