Re: Voltage controlled 10V->100V DC-DC converter
- From: John Fields <jfields@xxxxxxxxxxxxxxxxxxxxx>
- Date: Thu, 26 May 2005 18:09:59 -0500
On 26 May 2005 12:33:59 -0700, jwodin@xxxxxxxxx wrote:
>Output current is going to be in the low mA range, though I don't have
>an exact number (the load is almost entirely capacitive, with a very
>high R in parallel). I was hoping that the physical size would be
>something like 1"x1" on a PC board, if possible. And as far as
>efficiency, I assume you mean
>
>Power out / Power in ?
>
>If so, I can deal with very low efficiency. I'd have no problem having
>a standard rack HP power supply, or a few of them, powering the whole
>thing. As far as a control input voltage, I'll be controlling these
>DC-DC convters via CPU (with a National Instruments analog I/O board)
>that can supply -10V-10V analog (I can do digital too, but sounds more
>complicated).
I don't know much about switching supplies, but how about something
like this:
+12V>--+-----------------------------------+
| | Vc Vout
[L1] | 0-10 0-100
| | | /
+---[CR1>]--------------------------|---|---+--->>---+
| | | | |
| | | | |
C A---+ /+|--+ [R3] |
Q1 B--[R1]-+-Y NAND | A-------< | | +---+
E | B---+-+-Y NAND \-|------+ | |
| | | B---+ | | [C] [R]
| | | | | | | |
| | +--[R2]--+ | [R4] +---+
| | | | | |
| +--------[C1]-------+ | | |
| | | |
GND>---+-----------------------------------+-------+--->>---+
Basically a boost converter where the two NANDs form a gated
oscillator which turns Q1 on and off, forcing current through L1 and
then shutting it off abruptly which makes a spike that gets integrated
by C (your capacitor). As the stream of spikes charges C, the voltage
at the junction of R3 and R4 (a 10:1 voltage divider) rises until it
equals the voltage on the comparator's + input, at which time the
output of the comparator goes low, stopping the oscillator and turning
Q1 off. Then, when R (your load resistance) discharges C to the point
where the voltage on the - input of the comparator goes lower than the
voltage on the + input, the comparator's output will go high again,
starting the oscillator and recharging C.
--
John Fields
Professional Circuit Designer
.
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