Re: Beginner "reed relay" question
- From: martin griffith <martingriffith@xxxxxxxxxxxxx>
- Date: Tue, 31 May 2005 21:45:10 +0200
On 31 May 2005 12:01:15 -0700, in sci.electronics.design
dwfox1977@xxxxxxxxx wrote:
>I would like to know why my output voltage drops from 4.5V to 1.3V when
>I connect a reed relay (N/O type) from this voltage to ground.
>Further, I also need to know how to overcome this drop. I have a power
>supply of 9V in the system.
>
>
> 9 Volts Vcc
> |
> |
>0 or 5volts -----|------------------|
>0 or 5volts -----| MULTIPLEXER | Output goes from 4.5V down
>0 or 5volts -----| 4:16 | to 1.3 volts when relay is
>0 or 5volts -----|------------------| connected.
> ||||||||||||||||
> | ----------------- N/O
> | |
> --->|------------------|
> | REED RELAY | Need relay to make
> --->|------------------| these line common
> | | with each other.
> | ----------------- 3Volts
> __|__
> /////
>
>I have a 5 volt reed relay from radio shack. And, I have also ordered
>a 3 volt reed relay from digikey. Perhaps, there is a better way to do
>this though. All I need to do is make the Nomally open contact common
>with the 3 Volt contact as shown above. However, I need to use the
>output from the multiplexer to do this. Later, this will be controlled
>with a PIC chip (5 volts). But, for now, I just need these two lines
>to become common when a particular pin from the multiplexer is high.
>
>Thanks for any help you give,
>David
What Mux are you using? I used to use TTL compatable reed relays from
Pickering UK., normally connected from Vcc to the Mux output. You
could try using a 74HC0( insert favorite IC) buffer driven by the Mux
martin
.
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