Re: 3 dB bandwidth

In article <11bnuqqtlpucr71@xxxxxxxxxxxxxxxxxx>,
_see.web.page_@xxxxxxxxxxxxxxxxxx says...
>
>
>
> Don Bowey wrote:
>
> >Poop Bear wrote:
> >
> >> That forms a potential divider with a value of 0.5.
> >>
> >> Thats -6dB !
> >>
> >> Don't play semantics with your 10 log, 20 log stuff. I eat ppl like you for breakfast ! After which I'm employed to sort out their ***-ups.
> >
> >Where do you obtain the 0.5 value and what is the "potential" divider?
>
> The 0.5 appears to be correct, but the -6dB he pulled out of his arse.

Appears to be? Do you have a problem with *voltage* dividers? Do you
have a problem calculating 20log(.5)?

> If he had bothered to read the references I provided, or even done a
> basic web search, he would have found out that half the voltage equals
> -6dB but half the power equals -3dB. Alas, he is ineducable and thinks
> that aserting "0.5 equals -6dB" over and over again does not change the
> reality of 0.5 equaling -3dB when measuring power.

Umm, isn't 1/2 voltage = 1/4 power? ...thus 6bB, either way (funny how
the arithmetic works out).

> He is also too dim to realize how silly he looks flaming away at someone
> who has killfiled him and thus cannot see his posts.
>
LOL! You're priceless.

--
Keith
.

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