Re: Thinking about a 80MHz crystal - as a detector

From: Winfield Hill <Winfield_member@xxxxxxxxxxx>
Date: 31 Mar 2006 05:35:36 -0800

Fred Bloggs wrote...

Looking at crystal models, the loss-resistance element may
be on the order of 10 ohms, which implies a Johnson noise
density on the order of 0.4nV per root-Hz.

Prove it- what makes you think it is Johnson noise, because
it is represented as a resistor symbol?

Acckk, how am I going to do that? I'm making an assumption.
Maybe someone else can give us an answer, references, etc.

--
Thanks,
- Win
.

Follow-Ups:
- Re: Thinking about a 80MHz crystal - as a detector
  - From: Fred Bloggs

References:
- Thinking about a 80MHz crystal - as a detector
  - From: Winfield Hill
- Re: Thinking about a 80MHz crystal - as a detector
  - From: Fred Bloggs

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