Re: Current-driving a powerful IR-illuminator array
- From: szekeres@xxxxxxxx (GregS)
- Date: Fri, 31 Mar 2006 14:31:41 GMT
In article <122qe4949dsh4e4@xxxxxxxxxxxxxxxxxx>, "Meindert Sprang" <ms@xxxxxxxxxxxxxxxxxxxxxxxxx> wrote:
"BW" <bjorn@xxxxxxxxxxxx> wrote in message
news:1143810662.678320.268540@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Hi! I want to drive a fairly powerful IR-illuminator array using
high-efficiency IR-LED's (Agilent HSDL-4230 to be specific), which can
support continous currents of 100 mA and peak currents of up to 500 mA.
I want perhaps 40 of these.. and essentially I want to flash them all
in sync to an electronic camera shutter of around 1 ms width, with a
duty-cycle of perhaps 1-to-30. Now when googling around for suitable
circuits, most refer to relatively small power demands, with LEDs that
use a current of only a tenth of this.. both with resistors and with
MAX-circuits etc.
I once used the following approach to drive 25 IR leds in sync with a camera
frame sync: From a 12V power supply I drove 5 strings of leds, each string
having 5 leds in series. Each led string was connected anode to +12V,
cathode to the collector of an NPN transistor, the emitter was connected to
ground through a 10ohm resistor. By driving the base from 5V, the circuit
behaves like a current source of (5-0.7)/10 = 430mA. Need more current,
increase the drive voltage. All bases were connected together though a 10ohm
resistor.
The total current draw is 2.2 A while each led gets 430mA.
I still toying with a system to flash Led's in sync with a camera. Edmund Optics
makes a flasher, but its not heavy enough for my case.I don't see much of a problem
making my circuit, even though its going to peak at 65 watts. I probably will use Fet switching
to make the common connection at ground.
greg
.
- References:
- Current-driving a powerful IR-illuminator array
- From: BW
- Re: Current-driving a powerful IR-illuminator array
- From: Meindert Sprang
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