Re: How to superimpose 15V AC onto a 5000V DC
- From: "Genome" <mrspamizgood@xxxxxxxxxxx>
- Date: Tue, 13 Jun 2006 17:43:42 GMT
<vckishore@xxxxxxxxx> wrote in message
news:1150214891.558849.189000@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Luhan wrote:
vckishore@xxxxxxxxx wrote:
Hi all,
Please tell me how can I safely superimpose a 15Volt Ac signal (50Hz -
100KHz) from a signal generator onto a variable DC voltage (50V to
5000Volt). The output is 5000V DC + 15 V AC.
An you want to do this for what reason?
Luhan
hi luhan,
thank you for ur reply.
I need this for studying material properties, orientation of molecules
under a static+oscillating electric field.
do u have any ideas ?
Kishore
You might assume, hopefully, that the sample you are examining has a very
high DC resistance. I assume it is placed between a pair of plates to which
you apply your supply. Once these have been charged then effectively no DC
current will flow.
When you apply your AC voltage, through the transformer, then much of the
current flow will be capacitative and determined by the frequency and the,
separation and area of the plates along with the dielectric properties of
your material.
Your power supply will have a smoothing capacitance across its output
terminals and, as long as the value of this capacitance exceeds that of your
plates by a suitably large margin then the AC current will flow through that
capacitor and bypass any active parts actually within the supply.
Things should be safe without have to add any further components.
DNA
.
- References:
- How to superimpose 15V AC onto a 5000V DC
- From: vckishore
- Re: How to superimpose 15V AC onto a 5000V DC
- From: Luhan
- Re: How to superimpose 15V AC onto a 5000V DC
- From: vckishore
- How to superimpose 15V AC onto a 5000V DC
- Prev by Date: Re: MOSFET switching time...
- Next by Date: Re: Guillemin's Synthesis of Passive Networks
- Previous by thread: Re: How to superimpose 15V AC onto a 5000V DC
- Next by thread: Re: How to superimpose 15V AC onto a 5000V DC
- Index(es):
Relevant Pages
|
