Re: Question about opa350 data***


bill.sloman@xxxxxxxx wrote:

joakent@xxxxxxxxxxxxxx wrote:

Don't top post.

Is it also an adder? i.e. if instead of 2.5V from the divider we apply
any voltage, how will that affect the formula?

Ask your teacher.


See another poster arrived at (1+2*Rf/R)*(Vin-2.5V)+2.5V

Is this a follower? Is this an amplifeir?



...and what if after the divider (or thevenine equivalent) we have
a 60k resistor (which goes to the opamp minus) ?

The 60k resistor should only be carrying the bias current into the
input, so won't actually do anything to your signal.

If the input capacitance of the op amp you are using the usual couple
of picofrarads to ground, the 60k will insert a couple of hundred
nanoseconds of RC lag into the feeback loop, which might impair the
stability of the feedback loop.

I can't imagine why that would be, considering I am describing
to you an amplifier from a real commercial product, (of
prefessional quality)



--
Bill Sloman, Nijmegen

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