Re: absorbing reactance into series LC

On a sunny day (19 Feb 2007 05:50:53 -0800) it happened "Phil Newman"
<phillenium2002@xxxxxxxxxxx> wrote in
<1171893053.608857.67590@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>:


however, with the additional reactance (which is frequency invariant -
i.e constant)

jX = X + jwL - j/wC = 0

If your X is frequency invariant then it is a resistor.
If you have L C R in series (where R can be the resistance of the L),
then in resonance you will see R (real).
R also sets the Q factor of your series circuit, so its bandwidth.
http://en.wikipedia.org/wiki/RLC_circuit
.

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