Re: absorbing reactance into series LC

On Feb 19, 6:14 pm, "john jardine" <j...@xxxxxxxxxxxxxxxxxxxxx> wrote:
"Phil Newman" <phillenium2...@xxxxxxxxxxx> wrote in message

news:1171898397.535879.120540@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxx



If your X is frequency invariant then it is a resistor.
If you have L C R in series (where R can be the resistance of the L),
then in resonance you will see R (real).
R also sets the Q factor of your series circuit, so its bandwidth.
http://en.wikipedia.org/wiki/RLC_circuit

thanks for your answer.

However, I beleive the job of the susceptance/reactance is to shift
the resonant frequency of the LC series from w = 1 to another
frequency, which denotes the transmission zero of the filter.

Phil

It's very difficult to understand the wording.
It is possible to drop the resonant frequency to say 0.5 Rads, using just a
resistance. Maybe that's what's wanted in this case.
john

To drop the res freq you increase the inductance and/or capacitance.
Increasing resistance increases the bandwidth not the resonant
(center) frequency. Reactance is XL=2*pi*F*L, XC=1/(2*pi*F*C), so
changing the reactance requires change L, C, or F.







.

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