Re: square wave harmonic theory (time domain)

On May 31, 7:54 pm, Don Lancaster <d...@xxxxxxxxxx> wrote:
MooseFET wrote:
On May 31, 9:13 am, "Thomas Magma" <somewh...@xxxxxxxxxxxxxxxxxx>
wrote:

Imagine you have a tuned circuit with a very high Q being driven by
the squarewave. On each edge, the tuned circuit will be "shock
excited" and then start to ring down. This is like a bell being
struck, if you want to imagine a sound for it.

I'm not sure if this is a good analogy to help answer the original
question...if you strike a bell, it will ring at the resonant frequency of
the bell structure and not generate harmonic frequencies relating to the
rate in which you strike it.

The bell isn't generating anything. It really is a filter and in fact
its output will only have harmonics of the rate it is struck at.

So, if you blow into an organ pipe, all you get is the air you put in?

No, the Organ pipe is a nonlinear system. The fipple is a gain
element connected to the tuned system. The bell is a linear system
for the sizes of inputs we are considering.



The response of any dynamic system is the convolution of the driving
function and the natural function.

Agreed, if the system is linear. In the case of striking the bell at
a constant rate the frequency content of the input consists only of
harmonics of the rate of striking. Since the bell can't create new
frequencies, its output must also only contain those frequencies.


You have to consider both the transient and steady state responses.

I did.


.

Relevant Pages

  • Re: square wave harmonic theory (time domain)
    ... excited" and then start to ring down. ... This is like a bell being ... the bell structure and not generate harmonic frequencies relating to the ... its output will only have harmonics of the rate it is struck at. ...
    (sci.electronics.design)
  • Re: square wave harmonic theory (time domain)
    ... excited" and then start to ring down. ... This is like a bell being ... the bell structure and not generate harmonic frequencies relating to the ... its output will only have harmonics of the rate it is struck at. ...
    (sci.electronics.design)
  • Re: answer to YBMs bell problem
    ... the bell at the origin of A rings. ... saying that A won't ring as seen in frame B. ... An observer in B using t'=t will observe the ...
    (sci.physics.relativity)
  • Re: answer to YBMs bell problem
    ... Now getting back to the two bells that ring when light from both ... the bell at the origin of B will ... the frame of reference of A. Light is emitted at -a and a. ... An observer in B using t'=t will observe the ...
    (sci.physics.relativity)
  • Re: Contraction has been abolished by Special Relativity
    ... bell at the origin of S is to ring when light from both ends of the ... similar bell on the train would ring, ... are saying is that if an observer in S' cannot see light from both ...
    (sci.physics.relativity)
Loading