Re: The Electric Car
- From: John Larkin <jjlarkin@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx>
- Date: Tue, 25 Sep 2007 16:14:18 -0700
On Tue, 25 Sep 2007 15:56:27 -0700, BradGuth <bradguth@xxxxxxxxx>
wrote:
On Sep 25, 2:00 pm, John Larkin
<jjlar...@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx> wrote:
How might one harness the moon's kinetic energy, other than tide
power?
Via the LSE-CM/ISS tether dipole element should give us access to some
small percentage of that energy without causing great harm, such as
pulling that moon towards Earth might be worth avoiding, especially
since it's way too damn close for our own good as it is.
OMG, tethers now!
BTW, it's not actually orbital kinetic energy, but more like the raw
energy of gravity and centripetal related force
Force isn't energy. Gravity isn't energy. Only energy is energy. We
don't seem to be making progress here.
that's available, as
well as to whatever differential of teraVoltage and available amps of
electron flow that's worth extracting, and of course that's in
addition to whatever's solar and moon combined IR that should also be
impressive.
The kgf that's converted into terrestrial surface joules worth of what
What's the 2e20 joules/sec represent?
such a 7.35e22 kg orb that's being summarily flung about Earth, as
though on the end of an impressive string, that's clearly offset by
the mutual gravity of attraction. Obviously all that push-pull and
centripetal energy is going somewhere.
How much the moon loses to tidal
forces, ocean tides and heating the earth/moon crusts?
I believe the greater tidal force of the sun is actually in charge,
and if anything the moon is simply in the process of gaining energy as
extracted from Earth, not losing it. If it were losing energy it
would be getting closer to us, not further away. So, perhaps just
that alone is worth our tapping into.
You didn't answer my question: What does 2e20 joules/sec (what we dumb
engineers would call "watts") represent? How is that number arrived
at?
Imagine a gigantic weight, mounted on springs, that wiggles around
roughly once a day, driven by the moon's gravitation. Couple that
motion to a generator. Do the math.
That's true enough, as representing multiple teraWatts of perfectly
clean energy that's just going to waste. My LSE-CM/ISS and of its
dipole element might rather easily take some of that give and take
motion into account.
My proposal was sarcastic. You'd have seen that instantly if you could
do the math.
John
.
- References:
- Re: The Electric Car
- From: John Larkin
- Re: The Electric Car
- From: BradGuth
- Re: The Electric Car
- From: John Larkin
- Re: The Electric Car
- From: Eeyore
- Re: The Electric Car
- From: BradGuth
- Re: The Electric Car
- From: JosephKK
- Re: The Electric Car
- From: BradGuth
- Re: The Electric Car
- From: John Larkin
- Re: The Electric Car
- From: BradGuth
- Re: The Electric Car
- Prev by Date: Re: Low end desktop for EE tasks?
- Next by Date: Re: IR LED to repair remote control
- Previous by thread: Re: The Electric Car
- Next by thread: Re: The Electric Car
- Index(es):
Relevant Pages
|