Re: Debouncing....at About 1Mhz
- From: John Fields <jfields@xxxxxxxxxxxxxxxxxxxxx>
- Date: Thu, 01 Nov 2007 13:17:55 -0500
On Thu, 01 Nov 2007 08:17:25 -0700, John Larkin
<jjlarkin@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx> wrote:
On Wed, 31 Oct 2007 21:53:15 -0800, D from BC
<myrealaddress@xxxxxxxxx> wrote:
This has got to be a classic signal clean up problem....
I need a circuit that triggers on edge A, then ignores about 0.1uS of
jitter then triggers on edge B and then ignores a following 0.1uS of
jitter.
+-+ +-+ +----------------+ +-+ +-+
In | | | | | | | | | |
A | | | | B | | | |
-------+ +-+ +-+ +-+ +-+ +-----------
|<0.1uS>| |<0.1uS >|
|< 0.5uS >|
Out +------------------------+
| |
A' B'
-------+ +-------------
Edge A to A' is ~ less than 10nS
Edge B to B' is ~ less than 10nS
All values are approximates.
"In" and "Out" are repeating waveforms.
I think I can do it with:
1 flip flop
1 >0.1us delay circuit
Sprinkled with gates..
Or maybe I need 2 flip flops..one for edge A and one for edge B..
I'm not even sure yet which type of FF to get.
If anybody has done this problem before and doesn't mind sharing..let
me know a topology...
In the meantime, I'll be doodling until I get a solution...
D from BC
Looks like you can do it with a dflop, a quad xor, and an RC.
Run the input through a delay-line edge detector (three gates of
delay, then xor) and clock the dflop. Then rc lowpass the input and
apply it to D. Q is the output.
---
???
Edge A to A' is ~ less than 10nS
Edge B to B' is ~ less than 10nS
--
JF
.
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