Re: Transistors
- From: Jim Thompson <To-Email-Use-The-Envelope-Icon@xxxxxxxxxxxxxxx>
- Date: Sun, 18 Nov 2007 09:18:30 -0700
On Sun, 18 Nov 2007 15:54:10 GMT, JosephKK
<joseph_barrett@xxxxxxxxxxxxx> wrote:
Fred Abse excretatauris@xxxxxxxxxxxxxxxxx posted to
sci.electronics.design:
On Fri, 16 Nov 2007 16:32:35 -0700, Jim Thompson wrote:
On Fri, 16 Nov 2007 15:15:45 -0800, John Larkin
<jjlarkin@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx> wrote:
<snip>
+5V
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c
+10v----1K------b
e
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5K
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gnd
What is Vb? Ve?
John
John! You've created the universal employment test vehicle!
The amusing/distressing part of this is that no answers have been
forthcoming.
How about posting an E-mail address to send answers?
Then you can grade the respondents.
I'll lay you some side bets on who won't (be able to) answer ;-)
Assuming NPN, and 0.7V junction Vf:
Vb approx. 5.7V
Ve approx 5V
Ic is negative
I figure ib ~= ie ~=1.6 mA & 0.6 v Vbe.
Vb then is about 8.4 V and Ve 7.8 V.
Ic is well below uA.
Your grade = "F" ;-)
...Jim Thompson
--
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