Re: high-power voltage to current converter
- From: legg <legg@xxxxxxxxxxxxxxx>
- Date: Sat, 23 Feb 2008 11:59:44 -0500
On Sat, 23 Feb 2008 09:27:49 -0600, "Mook Johnson" <mook@xxxxxxxx>
wrote:
Yeah....driving any uncoupled inductive load produces the same loss in
"Robert" <renenkel@xxxxxxxxxxx> wrote in message
news:beb39c68-8677-4a73-8d65-728de0fa79e1@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
In case it makes things easier, my signal source is actually a
potentiometer, so if it is more convenient to have resistance rather
than voltage as the input, it is available. However, the
potentiometer cannot handle high currents. I was thinking of simply
attaching the potentiometer to the base of a large transistor, and
have the collector/emitter in series with the motor. But transistors
aren't linear near cutoff, so this won't work.
Robert
Depending on the range where you want to operate this will produce a HUGE
amount of heat. 1HP is ~750Watts. That 7.5A @ 100V If you run at low RPM
or in a stall condition, that would put 750W on the transistor and surely
blow it.
Your best approach is a PWM method.
You're looking for PWM torque control of a DC motor.
a linear driver as occurs when its driving a short circuit.
RL
.
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