Re: feeding ADC with too big input swing
- From: BW <bjorn.wesen@xxxxxxxxx>
- Date: Mon, 28 Jul 2008 02:16:44 -0700 (PDT)
On Jul 28, 1:17 am, Vladimir Vassilevsky <antispam_bo...@xxxxxxxxxxx>
wrote:
BW wrote:
What's your favorite trick of feeding a differential-input ADC with a
single-ended input (0-5V) that has twice the swing that the ADC
desires (0-2.5V differential, i.e. 1.25V +/- 0.625V for each input) ?
Resistor divider in half + op-amp buffer + single->differential op-
amp ? Is it possible with less components ?
It depends. AC or DC coupling, high or low frequency,
source/drive/referrence input impedance, how many channels, noise
requirements, etc.
For the low power low frequency, the minimum solution is something like
this:
http://www.abvolt.com/misc/single_diff.jpg
Hi, thanks for the reply!
Its definitely low-power (a monochrome video-signal), but the ADC
(LTC2202)
is sampling at 10 mhz and the signal is around half of that. One
channel,
DC-drive. Noise preferably in the ~100 uV range (I know this is larger
than
the 16-bit ADC LSB). My first idea was to simply use the LT1994 which
is in
one of Linears recommended input drives for the LTC2202, when
converting
a single-ended input. It's just that my input is 0-5V which requires
some
dampening.
Both would have the ground +
single-ended as inputs at some point anyway..
No. The whole thing can be fully differential.
I guess by separating the grounds of the single-ended input-device (a
sensor)
with the ADC-system you could have a differential input, if that is
what you
mean.
Best regards,
Bjorn W
.
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