Re: How much distortion is acceptable on residential utility power?
- From: Sylvia Else <sylvia@xxxxxxxxxxxxxxxxxxx>
- Date: Tue, 17 Mar 2009 22:29:12 +1100
MooseFET wrote:
On Mar 16, 9:14 pm, Sylvia Else <syl...@xxxxxxxxxxxxxxxxxxx> wrote:Phil Allison wrote:"MooseFET"MooseFet's analysis seems evidently correct. Why would the capacitor not
"Phil Allison"
The CFLs will tend to draw current over a wide part of the cycle.JESUS CHRIST you are ONE ARROGANT *** !!!!!!!!
** 100% WRONG !
The capacitor after the rectifier is small enough that the the ripple
is very large.
** Means the charging time is very short - fool.
No it doesn't. Where did you get that idea.
I posted ACTUAL data and YOU FUCKING SNIPPED IT !!
YOU *** - YOU FUCKING *** !!!!
----------------------------------------------------------------------
Go measure the current draw waveform of a few CFLs - instead of sitting
on you FAT ARSE making up WRONG theories and misinforming people.
Have look at figure 11 for a typical current wave.
Figure 12 shows the same lamp operated from a common triac dimmer at full
setting.
http://sound.westhost.com/articles/incandescent.htm#pf
The capacitor will start
charging when the mains voltage has passed the voltage that the
capacitor has discharged down to
** The charging time constant is very short for a CFL, typically about 50
uS.
Peak current is reached in 200-500uS and then drops off rapidly.
Go measure the current draw waveform of a few CFLs - instead of sitting
on you FAT ARSE making up WRONG theories and misinforming people.
Have look at figure 11 for a typical current wave - *** !!
Figure 12 shows the same lamp operated from a common triac dimmer at full
setting.
http://sound.westhost.com/articles/incandescent.htm#pf
start charging as soon as the input voltage (minus the forward rectifier
drop) reaches the capacitor's voltage? Why would it stop charging before
the input voltage peaks?
On ones other than the weird Ecofriendly brand:
The voltage will droop enough that it hits the sine wave about 30
degrees before the peak. The ripple will be about 20% of the
voltage. At that point, the sine wave has a fairly fast slew rate so
I'd expect a fairly high current during the early part of the charging
and then a drop to a lower current for the rest of the pulse.
Since the current is porportional to the rate of change of voltage, for an input wave sine x the current will follow cos x while the rectifier is forward biased.
Sylvia.
.
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