Re: Motion detector
- From: "Trevor Wilson" <trevor@xxxxxxxxxxxxxxxxxxxxxxxxx>
- Date: Sat, 26 Dec 2009 12:58:25 +1100
"Sylvia Else" <sylvia@xxxxxxxxxxxxxxxxxxx> wrote in message
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Trevor Wilson wrote:
"Sylvia Else" <sylvia@xxxxxxxxxxxxxxxxxxx> wrote in message
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Trevor Wilson wrote:
Sylvia Else wrote:It might be, but it's not the power consumed by the load that is the
Trevor Wilson wrote:**As was I. The POWER consumed by the device using a relay will probaby
"Sylvia Else" <sylvia@xxxxxxxxxxxxxxxxxxx> wrote in messageAs Phil has pointed out, and you have conceded, the PFs are different,
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Trevor Wilson wrote:**It is very relevant. The leakage current through a typical
"Phil Allison" <phil_a@xxxxxxxxxx> wrote in messageIt didn't, and doesn't, seem relevant though, given that my point
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"Trevor Wilson"**Misunderstanding and poor wording by me. I do not dispute the
"Phil Allison"** Huh ????
**Indeed it is, unless it the relay contacts happens to be in**Complete bollocks. A TRIAC has miniscule leakage. Less** The leakage current flowing in such a suppression cap
leakage current, in fact, than the suppression capacitor
across the relay contacts. MUCH less.
produces no heat and consumes no power.
Cos the PF is zero.
series with a resistive load (like an incadescent lamp).
Cold lamps have typical resistances under 100ohms
The AC current from a 47nF cap at 240 volts is 3.5 mA
Do the math.
I get a PF of 0.0014
Over to you.....
PF. I was making the point that the current through a typical
suppression cap exceeds the leakage current through a typical
TRIAC. It was for Sylvia's benefit, since you already knew that.
related to power consumption.
suppression cap across a relay is in the order of milliamps. The
leakage across a tyical TRIAC is in the order of microamps. The use
of a relay in such an application does not guarantee zero power
consumption when non-operational.
and I was clearly focussing on power, not current.
be significantly higher than if it uses a TRIAC. The reason is that the
current flowing through the load will be much higher with a relay.
main concern.
**Yes, it is.
It is the power consumed by the switching element, since
it is where most of the voltage drop occurs.
**Change of discussion, duly noted. There will be a Voltage drop across
any semiconductor, whilst there will be essentially zero drop across
relay contacts. THAT, however, is not your original contention.
The TRIAC is essentially
resistive, so it is consuming real power.
**Wrong. The TRIAC is essentially a solid state switch. It does, however,
dissipate some power, due to the valtage drop across the device. A relay
(usually) exhibits a far lower Voltage drop.
Remember, we're talking about the off state. The voltage drop across the
device is the input voltage, near enough.
**Correct. Since the off state of a TRIAC exhibits a leakage current in the
order of a few microAmps, it is several orders of magnitude less than the
current flow through a typical suppression cap across relay contacts.
The relay, with a capacitor
across its contacts, is only consuming reactive power, for which there
is no charge to a retail customer.
**WRONG! The capacitor across the contacts allows a small current to flow
into the load at all times. This power will certainly be charged to the
consumer. A TRIAC, OTOH, will usually allow a much smaller current to
flow into the load. Thus, the consumer will pay less.
Your ignoring the power dissipated in the TRIAC.
**Well, no, I'm not. The Pdiss is miniscule in the off state.
That's most of the
power consumption of the combined system in the off state.
**Yes, it is. It is also far less than the Pdiss of the load, when using a
relay. The TOTAL power consumption of a TRIAC device (when connected to the
load) is generally lower than a relay device.
--
Trevor Wilson
www.rageaudio.com.au
.
- References:
- Motion detector
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- Re: Motion detector
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