Re: E <=> MC^2 generally ...and also inside living things!
From: Harry Conover (hhc314_at_yahoo.com)
Date: 08/10/04
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Date: 10 Aug 2004 15:42:18 -0700
John Larkin <jjlarkin@highlandSNIPtechTHISnologyPLEASE.com> wrote in message news:<juohh0plrgp8gdtnmidpkm2ei9j40ksctn@4ax.com>...
> On 10 Aug 2004 05:24:42 -0700, abdul.ahad@ntlworld.com (AA Institute)
> wrote:
>
> >I don't know much about this topic so I'm not going to pretend...
> >Generally, during detonation of an atom bomb, mass is converted into
> >energy in accordance with the famous equation of E=MC^2 and I believe
> >the highest efficiency of conversion of mass into energy in such a
> >reaction has been observed to be less than 10% (is it 8%?). I have 2
> >questions in relation to this:-
> >
>
> Nukes don't turn *real* mass (ie, whole particles) into energy, they
> just shuffle nuclear binding energy around, so efficiency of apparent
> mass to energy conversion a tiny fraction of a percent. To truly turn
> mass to energy you should destroy some genuine mass in a
> matter-antimatter reaction, which is 100% efficient at the
> emm-cee-squared thing.
John, the result of all nuclear energy liberating reaction is a
product whose collective net mass is less that the mass of the
components used to create the reaction. This is where E=MC^2 enters
the scene.
The loss in mass will alway EXACTLY equal the amount of energy
released.
Actually, it's a pretty simple concept, once you understand it, and it
has been experimentally tested at many scales.
Forget your matter-antimatter reactions, and focus your future
attention on a good, university level, introductory, nuclear physics
text and less on the coffee-table/sci-fi crap.
Harry C.
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