Re: how much electricity (watts) can be produced?
- From: "Fritz Schlunder" <me@xxxxxxxxxxx>
- Date: Tue, 15 Nov 2005 17:02:58 -0700
"kelvin" <rockkelvin@xxxxxxxxx> wrote in message
news:1131989531.472183.111390@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
> Hello there everyone!!
>
> I would like to know that how much electricity (watts) can be produced
> if a 10,607,142.87 litres of water that is stored in header tanks, is
> flow 'downward' to a turbine?
>
> Thank you!!
The potential energy of the water is mgh. That is:
E(potential)=m*g*h
Where E(potential) is the potential energy of the water measured in joules,
m is the mass of the water measured in kilograms, g is a constant equal to
9.81 meters per second squared (at the surface of earth), and h is the
height in meters that the water is stored at above the outlet of the water
turbine.
Water has a density of roughly 1g/cm^3, so 10.6 mega liters should mass
around 10.6 million kilograms.
So for example, imagine all of the water is stored 100 meters above the
outlet of the water turbine. In this case
E(potential) = 10,600,000*9.81*100 = 10.4 gigajoules.
A watt is a joule per second, so if all of that water was allowed to drain
over say a one second period, you would generate 10.4 gigawatts of
electricity (less turbine and generator efficiency loss, which is not very
much since water turbines and generators can be very efficient, perhaps
>90%), albeit only for one second. On the other hand, if you drained it in
say a one day period (86400 seconds in a day), the power output in watts
would be 10.4 GJ/86400 s = 120 kilowatts.
.
- References:
- how much electricity (watts) can be produced?
- From: kelvin
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