Re: circumventing Lenz

Hi Daestrom,

That all said, I came across another US patent, this time granted, which
has the same scheme. That is inducing current in closed core coils.
These people actyally tested a few setups and stopped only short of
exactly that which you contest. I suggest you look at the test numbers,
graph them out and extend the curves just enough to realize the
significance of the real world as opposed to the theoretical one.

Here is the link:

http://www.freepatentsonline.com/6208061.pdf

My kind regards, Slavek.






daestrom wrote:

"slavek krepelka" <slavek.krepelka@xxxxxxxxxxxx> wrote in message
news:43FEB02E.665CE5E6@xxxxxxxxxxxxxxx
Whatever Plan B is,

Plan B wrote:

Sorry but this doesn't "circumvent" Lenz's Law

Hmm, if you had any sensible understanding of the simple fact that
magnetically unsaturated ferromagnetic closed frame will contain a
magnetic field of a coil wrapped around it, like for example a classic
transformer wound with two separate coils on an angular O core contains
their magnetic field, you would stand a chance to understand that such
closed core, even if shaped as I have shaped it, will again contain the
magnetic field of induction coils within its material, rather than blast
it through the gap and first resist the approach of a magnetic finger,
then its recession.


The fact that ferromagnetic materials produce a low reluctance path for flux
is not enough. First, the 'magnetic fingers' must send its own magnetic
lines of flux across the gap into your unique core design in order to induce
a voltage into the windings. And it must continue to do so, even when a
load current is applied.

When any load current flows through the windings, it will create a
magneto-motive force that opposes the lines of flux in the core from the
external, 'magnetic fingers'. The result is the 'pathway' for the external
'magnetic finger's lines of flux is impeded by this new magneto-motive
force. This will affect the net flux (summation of excitation and winding
fluxes) that is inducing the voltage. The result is your machine will take
very little torque to turn it, but it will produce very little electrical
power.

You're trying to design a machine that can output electrical power without
inputting a significant amount of mechanical power. That right there should
be a clue that you may have overlooked something.

<snip>
This is either a hoax, or the interpretation of physics is wrong; try
again.

No interpretation of physics whatsoever my dear Plan B. Just a bit of
observation, common sense and creativity.

Your observations are incomplete. You obviously haven't built one yet and
measured its performance. You need to analyze how both the magnetic field
of the excitation magnet and that of the load current in the coils will
interact. (yes, they *will* interact, since the excitation flux *must*
enter your core for induction to occur).

While the interactions may only present a modest restraining torque on the
input shaft, the interactions will also reduce the induced voltage to the
point where very little output power can be generated. Even a tiny amount
of load current will create enough magneto-motive force as to completely
stop almost all excitation flux from entering the core. No appreciable
excitation flux, no appreciable induced voltage.

To use your transformer analogy, you have a single-winding transformer. Now
you're trying to induce a voltage into that coil by moving a magnet across
the exterior of the transformer core. With the winding open-circuited, you
*can* induce a significant voltage. But the instant you apply a load and
have current flow through the winding, the magneto-motive force of the small
current through many turns of the winding will 'overpower' the external
magnet and reduce all induction to nil.

Put another way, the 'voltage regulation' of such a machine will be very,
very poor. Almost any load current will drop the output voltage to a very
low value, resulting in total electrical power output to be very small. (the
power output will be commensurate with the mechanical power needed to turn
the shaft).

daestrom
.

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